balance the equation:
2HCl + CaCO3 >> CO2 + H2O + CaCl2
figure the moles of calcium carbonate:
3.25/molmassCaCO3
then you must need twice that of acid.
2*3.25/molmassCaCO3 = volume*.2M
solvefor volume in liters. change to milliliters.
How many milliliters of 0.200M HCl can react with 3.25g CaCO3?
1 answer