13 g of Zn is 13/65.4 = 0.199 moles. You might as well round that off to 0.20 moles. You will require 0.4 moles of HCl for complete reaction.
That would be contained in 1 liter of a 0.4 molar solution.
One liter is 1000 ml.
how many mililiters of a 0.4 molar HCl solution are needed to react completely with 13 grams of zinc according to the following equation?
Equation.
2 HCl + 1 Zn -----> 1 ZnCl2 + 1 H2
1 answer
1 answer