If you are breaking one = per fluorene, then it takes two hydrogens to do that, from the borohydride.
So for each mole of borohydride, you can break reduce two fluorenone molecules of the double bond.
How many mg of fluorenone can 0.53mol of sodium borohyride(NaBH4) reduce?
~I don't know how to get this..wouldn't I have to have a reaction equation given to me??
Well I didn't have one for the question given to me so I don't know what to do. I tried looking for the reaction online but came up empty handed unfortunately.
Could someone help me out on this?
Thank You =)
2 answers
Thank You Bob