you need to know how many cm of rain fell and the area of the city.
1 cm^3 = 10^-3 kg = 10^-6 tons
need depth of water in cm * area of city in cm^2 to get volume in cm^3
multiply that by 10^-6 to get tons.
How many metric tons (1 metric ton = 10^3 kg) of H2O fell on a city? (1cm^3 of H2O has a mass of 1g = 10^-3 kg)
Thus far I have:
10^-3 Kg x (1 metric ton/10^3)
but I don't understand the significance of adding 1 cm^3 to the problem.
1 answer
1 answer