How many liters of nitric acid are needed to neutralize 25mL of 4.2M calcium hydroxide?

2 answers

the reaction is:

2HNO3 + Ca(OH)2 --> Ca(NO3)2 + 2H2O

we know the mole of calcium hydroxide
n=cv = 4.2mol/L x 0.025L = _____

this mole needs to be neutralized by the acid. so we need to calculate the mole of nitric acid using the mole ratio from the balanced equation;

2 mole of nitric acid neutralize 1 mole of calcium hydroxide.

2:1
x:____(the mole of calcium hydroxide)

where x is the mole of nitric acid. use that mole to calculate the volume..can you???..we need a concentration of nitric acid...is there a concentration for nitric acid??? check again..
41ml