You didn't balance the equation so I have done that.
2K + 2H20 = 2KOH + H2
mols K metal = grams/atomic mass = 22.3/39.1 = 0.570
The equation tells you with the coefficients aht 2 mols K will produce 1 mol H2 gas; therefore, 0.570 mols K will produce0.570/2 mols = ?
Then PV = nRT. You know P and n and R (8.314 if you use kPa), and T is 295 K. Solve for V in liters. Post your work if you get stuck
How many liters of hydrogen gas can be produced as 295k and 99.0 kPa if 22.3 grams of potassium metal react with excess water?
2K + H20 = 2KOH + H2
3 answers
I think I have the correct answer, but would the answer be 6.50 L of hydrogen gas?
NOPE. I'll find the error if you show you set up and the math.
0 answers