When ONLY volume is involved, you may consider it the same as volume (liters), therefore,, look at the balanced equation.
CH4 + O2 ==> CO2 + 2H2O
The equation says that for every liter of CH4 burned we obtain 1 liter CO2 + 2 liters H2O; voila, 1L + 2L = 3L.
How many liters of gasesous methane (CH4) must be burned in oxygen to produce enough H2O and CO2 to fill a 3.0 L balloon?
Assume that H2O and CO2 are the only combustion products and that the temperature and pressure remain constant.
How would I solve this?
Attempt: 3.OL (1 mol/ 22.4L)
the answer is 1.0L
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