how many liters of a 10%solution of acid should be added to 20 liters of 60%solution of acid to obtain a 50%solution?
4 answers
This looks like a chemistry assignment.
Assuming the density doesn't change and the solutions mix with no volume change, the following should do it.
L = liters we need to add.
L(10) + 20(60) = (L+20)*50
Solve for L.
L = liters we need to add.
L(10) + 20(60) = (L+20)*50
Solve for L.
Frank=
You should show the subject matter in the heading. In this case the heading should have been chem or math. Had it not been for Ms Sue, I wouldn't have looked at anything called journal assignment
You should show the subject matter in the heading. In this case the heading should have been chem or math. Had it not been for Ms Sue, I wouldn't have looked at anything called journal assignment
how many liters of a 10%solution of acid should be added to 20 liters of 60%solution of acid to obtain a 50%solution