Asked by nakul
How many license plates can be made if each should have 3 letters of the English alphabet with no letter repeated ? what will be the answer if the letters can be repeated?
Answers
Answered by
nakul
Matrix method
X-y+3z=2
-2x-2y+z=3
2x+y+2z=2
X-y+3z=2
-2x-2y+z=3
2x+y+2z=2
Answered by
Steve
plates:
no repeated letters:
there are 26 choices for the 1st letter, leaving only 25 for the 2nd, and 24 for the 3rd: 26*25*24 = 15600
repeated letters:
26*26*26 = 17576
matrix:
If the matrix of coefficients is A, you want (x,y,z) such that
AX = B
where B = (2 3 2)
That means that X = A<sup>-1</sup>B
http://www.wolframalpha.com/input/?i=solve+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}*{{x}%2C{y}%2C{z}}+%3D+{{2}%2C{3}%2C{2}}
A<sup>-1</sup>:
http://www.wolframalpha.com/input/?i=inverse+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}
A<sup>-1</sup>B:
http://www.wolframalpha.com/input/?i=%28inverse+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}%29*{{2}%2C{3}%2C{2}}
no repeated letters:
there are 26 choices for the 1st letter, leaving only 25 for the 2nd, and 24 for the 3rd: 26*25*24 = 15600
repeated letters:
26*26*26 = 17576
matrix:
If the matrix of coefficients is A, you want (x,y,z) such that
AX = B
where B = (2 3 2)
That means that X = A<sup>-1</sup>B
http://www.wolframalpha.com/input/?i=solve+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}*{{x}%2C{y}%2C{z}}+%3D+{{2}%2C{3}%2C{2}}
A<sup>-1</sup>:
http://www.wolframalpha.com/input/?i=inverse+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}
A<sup>-1</sup>B:
http://www.wolframalpha.com/input/?i=%28inverse+{{1%2C-1%2C3}%2C{-2%2C-2%2C1}%2C{2%2C1%2C2}}%29*{{2}%2C{3}%2C{2}}
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