How many kJ of heat are required to convert 1.00 g of ice at -25°C to steam at 125°C?
s(ice) = 2.108 J/g·°C
s(liquid water) = 4.184 J/g·°C
s(steam) = 1.996 J/g·°C
heat of fusion = 6.01 kJ/mol
heat of vaporization = 40.79 kJ/mol
1 answer
https://www.jiskha.com/questions/14154/how-much-heat-is-added-to-a-10-0-g-of-ice-at-20-0-degrees-celsius-to-convert-it-to-steam