Enthalpy released is 1107 for this reaction.
2Ba(s) +O2(g) --> 2BaO(s) so that is 1107/2 for this reaction:
Ba(s) + 1/2 O2(g) --> BaO(s) dH = -553.5 kJ for 137.3 kJ so for 15.75 g Ba it will be
553.5 kJ x (15.75/137.3) = ?
Check all of those numbers. Post your work if you have questions or you get stuck.
How many kJ of heat are released when 15.75 g of Ba reacts completely with oxygen to form BaO?
The enthalpy for the reaction below is -1107 kJ.
2Ba(s) +O2(g) --> 2BaO(s)
Group of answer choices
20.8
63.5
114
70.3
127
2 answers
Just give me the answer