How many kilojoules of heat is required to completely covert 60.0 grams of water at 32.0° C to steam at 100°C?

Question

For water:
s = 4.179 J/g °C
(delta)H fusion = 6.01 kJ/mol
(delta)H vap = 40.7 kJ/mol

Answer 1

q1 = heat to move H2O from T = 32 C to 100 C.
q1 = mass water x specific heat water x (Tfinal-Tinitial)

q2 = heat to vaporize water at 100 to steam at 100.
q2 = mass water x delta Hvap.

Total heat required = q1 + q2.