How many kilojoules of energy would be liberated by condensing 48.03 mol of steam initially at 110.0 °C and then allowing the liquid to cool to 32.9 °C?

Answer 1

you have three factors;
heat to remove to cool steam to 100C:
heat to condense steam at 100C:
heat to remove to cool water from 100 to 32.9C.

I assume you can do these, you may not have the heats of vaporization and specific heats in mole units, if not, convert 48.03 moles to kg.