How many kilojoules of energy are needed to convert 104 g of ice at -14.6 to water at 25.8°C? (The specific heat of ice at -14.6 is 2.01 J/g°C.)

1 answer

you can use the equation:
c=heat transferred/mass X change in temperature
c=2.01J/gC
mass= 104g
chaneg in temp = 40.4C

2.01= x/ 104g x 40.4C

x=8445.21J then divide that number by 1000 to get kJ the answer is 8.44kJ

you can check my calculations but that should be the correct equation.