so the setup would be
(20.0)(80)=1600cal?
How many kilocalories of heat are required to melt 20.0 kg of ice at 0°C?
Okay so the given is
m=20.0kg
Ti=0°C
HeatFusionIce=80 kcal/kg
2 answers
right
Okay so the given is
m=20.0kg
Ti=0°C
HeatFusionIce=80 kcal/kg
2 answers
1 answer
1 answer
6 answers
2 answers