How many kilocalories are released when 25.0 grams of steam, originally at 165oC, is cooled to form liquid water at 35oC?

Answer 1

q1= heat released in going from 165 C to 100 C.
q1 = mass steam x specific heat steam x (Tfinal-Tinitial) where Tfinal = 100 C and Tinitial = 165 C

q2 = heat released by condensation from steam @ 100 to liquid @ 100 C.
q2 = mass steam x heat vaporization

q3 = heat released in going from 100 C liquid to 35 C liquid.
q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial) where Tfinal = 35 C and Tinitial = 100 C

qtotal = q1 + q2 + q3 = ?
Note: q1 and q2 and q3 will be negative since q will be negative for heat released.
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