q = mass H2O x delta Hvap.
You don't need the specific heat H2O. You need the delta H vaporization/condensation.
How many joules of heat need to be removed to condense 1.50 kg of steam at 100°C
-Specific Heat for steam is 2000 J/kg°C-
3 answers
Thank you for clearing that up
(1.50*2.26*10^6)= 3.39*10^6 J
(1.50*2.26*10^6)= 3.39*10^6 J
I agree