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Original Question
How many kilojoules of heat is required to completely covert 60.0 grams of water at 32.0° C to steam at 100°C? For water: s = 4...Asked by har
How many joules of heat are required to completely covert 85.0 grams of water at 40.0° C to steam at 100°C?
For water: c = 4.179 J/g °C Hfusion = 6.01 kJ/mol Hvap = 40.7 kJ/mol
For water: c = 4.179 J/g °C Hfusion = 6.01 kJ/mol Hvap = 40.7 kJ/mol
Answers
Answered by
DrBob222
q1 = heat needed to raise T of liquid water from 40 C to liquid water at 100 C.
q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q2 = heat needed to convert water at 100 C to steam at 100 C.
q2 = mass H2O x heat vaporization.
Total q = q1 + q2.
By the way, it helps us help you better if you use the same screen name. You don't fool anyone but it confuses us.
q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q2 = heat needed to convert water at 100 C to steam at 100 C.
q2 = mass H2O x heat vaporization.
Total q = q1 + q2.
By the way, it helps us help you better if you use the same screen name. You don't fool anyone but it confuses us.
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