How many joules of heat are required to completely covert 85.0 grams of water at 40.0° C to steam at 100°C?

For water: c = 4.179 J/g °C Hfusion = 6.01 kJ/mol Hvap = 40.7 kJ/mol

1 answer

q1 = heat needed to raise T of liquid water from 40 C to liquid water at 100 C.
q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial)

q2 = heat needed to convert water at 100 C to steam at 100 C.
q2 = mass H2O x heat vaporization.

Total q = q1 + q2.
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