How many joules of heat are lost by 3399kg granite as it cools from 41.7 degrees Celcius to -13.3 degrees Celcius? answer must be in joules not kJ

Answer 1

q = mass granite x specific heat granit x delta T.

Answer 2

ok so,

q=3399kg x 0.803 x 55
q = 150.116

Is that correct?

Answer 3

so then my answer would be 150.116kJ which equals 150116835J. Is that correct???