how many ions and moles does 113 mL of .490 M aluminum chloride have?
2 answers
Molarity = moles/liters so moles = molarity x liters. 113mL = .113L so .113 x .490 = 0.05537moles. as far as the ions go, i think you would have to look at a periodic table and convert the molecular weight or something. that's a strange question, im not sure if you are wording it right. hope this helps
AlCl3.
Wendell is correct for moles AlCl3 = M x L = ??
Then moles Al = the same as moles AlCl3 since there is 1 mole Al per 1 mole AlCl3.
For moles Cl, it is 3xmoles AlCl3 since there are 3 Cl atoms per molecule AlCl3.
Wendell is correct for moles AlCl3 = M x L = ??
Then moles Al = the same as moles AlCl3 since there is 1 mole Al per 1 mole AlCl3.
For moles Cl, it is 3xmoles AlCl3 since there are 3 Cl atoms per molecule AlCl3.
1 answer