first such number -- 102
last such number -- 198
(198-102)/6 = 16
but !! .....
let's look at the first 4 of our numbers:
102 108 114 120
if I follow my above method
I would get (120-102)/6 = 3
notice I would not be counting the very first number
so our answer of 16 should be increased by 1
number of integers between 100 and 200 which divide evenly by 6 are 17
Can you generalize my method?
How many integers between 100 and 200 are divisible by 6? (are there any shortcut method to get this?)
2 answers
17