how many grams of ZnCl2 are needed to prepare 250 ml of an aqueous solution with an osmolarity equal to 0.300?

1 answer

An osmolarity of 0.3 osm = 0.1M ZnCl2 (since there are three particles in a molecule of ZnCl2).
You wnat how many mole? That is M x L = ?
The moles ZnCl2 = grams ZnCl2/molar mass.