Asked by Jack
How many grams of steam at 100C must be mixed with 200g of water at 20C in order for the equilibrium temperature to be 50C?
Answers
Answered by
bobpursley
the sume of heats is zero...
Heat to heat water + heat or condense steam+heat to cool steam=0
200*cw*(50-20)+Hv*m + m*Cw*(50-100)=0
solve for mass m.
Heat to heat water + heat or condense steam+heat to cool steam=0
200*cw*(50-20)+Hv*m + m*Cw*(50-100)=0
solve for mass m.
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