NaI = 23 + 127 = 150 grams/mol
2 mol NaI is therefore 300 g
I2 is 2*127 = 254 g/mol
2 NaI --> 2 Na + I2
88.1 /254 = mols I2
= mols 2Na = x/300
x = (300/254 )88.1
How many grams of sodium iodide, NaI, must be used to produce 88.1 g of iodine, I2
1 answer
1 answer