how many grams of silver chloride are produced when 45 grams of calcium chloride react with excess silver nitrate?

3 answers

This is a basic stoichiometry problem.

1. Write and balance the equation.
2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2

2. Convert what you have, in this case 45 g CaCl2, to moles. moles = grams/molar mass = 45/molar mass CaCl2 = ?? moles CaCl2

3. Using the coefficients in the balanced equation, convert moles of what you have (CaCl2) to moles of what you want (in this case moles AgCl).
??moles CaCl2 x (2 moles AgCl/1 mole CaCl2) = ??moles x (2/1) = xx moles AgCl

4. Now convert moles AgCl to grams. g = moles x molar mass.

180 AgCl?

its 110