I forgot to add the equation so here it is:
2KNO3(s) ---> 2KNO2(s) + O2(g)
How many grams of potassium nitrate (KNO3) are required to produce 536 g of potassium nitrite (KNO2) according to the equation below?
*I've tried this question for so long and I get so many different answers in the end so please help.
4 answers
The mole ratio is 1:1, so figure the moles of potasium nutrite in 536g.
Then figure the number of grams in that same number of moles of postassium nitrate.
Then figure the number of grams in that same number of moles of postassium nitrate.
Moles of potassium nitrite (in 536g) would be 6.29 or 6.3 moles, correct?
Yes but I would keep the 6.29 since the 536 allows for three significant figures. Don't throw numbers away unless it's necessary.
4 answers