How many grams of O2 will be formed from 3.76 g of KClO3?
please guide me with solution so I can it answer thank you! (chemistry is so harddd :(((. )
6 answers
So what is the reaction with?
if you're gonna judge me by that reaction, u can call me dumb because I have a problem understanding a simple problem it takes me days or even weeks.
Well I can tell you how many grams of O are in the KClO3. However I have no idea what the chemical reactants are. For example if there is H2O on the right, then O results that is not in the O2 resulting. Therefore I can not help if you do not tell me what the problem is about.
1 mol of KCO3
is 39 + 35.5 + 3*16 = 122.5 grams containing 48 grams of O
so you have (48/122.5) * 3.76 = 1.47 grams of oxygen in the original stuff. Again I do not know how much O is in the rest of your equation.
1 mol of KCO3
is 39 + 35.5 + 3*16 = 122.5 grams containing 48 grams of O
so you have (48/122.5) * 3.76 = 1.47 grams of oxygen in the original stuff. Again I do not know how much O is in the rest of your equation.
2KClO3 ==> 2KCl + 3O2
Thanks DrBob!
In that case, just use what I did, no change in grams of O from left to right.
In that case, just use what I did, no change in grams of O from left to right.
2KClO3 ==> 2KCl + 3O2
mols KClO3 = grams/molar mass = 3.76/122.5 = approx 0.031
Now convert mols KClO3 to mols O2 using the coefficients in the balanced equation. 0.031 mols KClO3 x (3 mols O2/2 mols KClO3) = 0.031 x 3/2 = ?
Remember that 0.031 number is rounded.
Then grams O2 = mols O2 from previous step x 32 = ?
However, notice this is the same answer anonymous gave you. A problem anonymous had with your post was you didn't say what substance you're reacting with the KClO3 nor how you're getting the O out of the KClO3. You should have said that the KClO3 was heated to produce the O2. The way anonymous worked the problem and the way I worked the problem was to assume you heated and decomposed the KClO3 to form the oxygen.
mols KClO3 = grams/molar mass = 3.76/122.5 = approx 0.031
Now convert mols KClO3 to mols O2 using the coefficients in the balanced equation. 0.031 mols KClO3 x (3 mols O2/2 mols KClO3) = 0.031 x 3/2 = ?
Remember that 0.031 number is rounded.
Then grams O2 = mols O2 from previous step x 32 = ?
However, notice this is the same answer anonymous gave you. A problem anonymous had with your post was you didn't say what substance you're reacting with the KClO3 nor how you're getting the O out of the KClO3. You should have said that the KClO3 was heated to produce the O2. The way anonymous worked the problem and the way I worked the problem was to assume you heated and decomposed the KClO3 to form the oxygen.