How many grams of O_2(g) are needed to react completely with 3.95 g of H_2(g) according to the following balanced chemical equation: 2H_2(g) + O_2(g)--> 2H_2_O(g)

Question

Molarity (M) is the number of moles of a solute per 1 L of solution--> M= (mol solute)/(L solution). How many moles of permanganate are in 8.23 L of a 3.78 M solution?

Answer 1

steps:
how many moles of H2 is 3.95g?
you need for each mole of H2, half as many moles of O2?
how many grams is that?

moles=molarity*liters

Answer 2

@bobpursley
Molarity= 3.78/8.23= 0.459
0.459=molarity
0.459 x 8.23= 3.78moles

Answer 3

I got 31.6 g of O2 for #1 is that correct?