N2 + 3H2 ==> 2NH3
mols N2 = 2.89
Convert to mols NH3 using the coefficients in the balanced equation.
2.89 x (2 mols NH3/1 mols N2) = 2.89 x 2/1 = ?
Then g NH3 = mols NH3 x molar mass NH3 = ?
How many grams of NH3 can be produced from 2.89mol of N2 and excess H2.
Express your answer numerically in grams.
2 answers
9.5