The correct answer is b) 12.90 grams of NaOH.
To calculate the grams of NaOH present in 3.1 moles, use the formula:
Grams = Moles x Molar Mass
Grams = 3.1 moles x 39.997 grams/mol = 123.99 grams
Therefore, there are 123.99 grams of NaOH in 3.1 moles of NaOH.
How many grams of NaOH are present in 3.1 moles of NaOH. (The molar mass of NaOH is 39.997 grams/mol) If you are unsure how to convert moles to grams, please see the example problem linked HERE. a 0.078 grams of NaOH b 12.90 grams of NaOH c 123.99 grams of NaOH d 43.10 grams of NaOH
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