How many grams of NaN3 are needed to produce 20.0 L of N2(g) at 30.0 oC and 776 mmHg ?

Answer 1

well, 2 moles of NaN3 will give 3 moles of N2

soconverting 20 l at above, to STP...
moles=20/22.4 *(273/303 )=.80 moles
so we want 2/3 * .8 moles naN3, or grams= 1.6/3 * 65g=34.7 grams