You want a 0.9% solution of NaCl (by mass).
That is 0.9g/100 mL soln. So you want for 1000 mL just 0.9 g x (1000 mL soln/100 mL soln) = 9 g/L.
How many grams of NaCl should be added to 1 L of water to make an isotonic solution? (molecular weight of NaCl= 58.5)
Can someone please explain to me why the answer is 9 grams.
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