How many grams of MgCl2 is needed to make 1200ml of a .25M solution?
.25M/L* 1200mL/1* 1L/1000mL* 95.211:-/ mol
I got 28.563g
1 answer
Your answer is correct but you have too many significant figures listed. You're allowed only 2. That means to round your answer to 29 g.