To determine the number of grams of magnesium chloride in 75.0 mL of a 200 M solution, we need to use the equation:
Grams of solute = (Molarity of solution) x (Volume of solution in liters) x (Molar mass of solute)
Given:
Molarity of solution = 200 M
Volume of solution = 75.0 mL = 75.0/1000 L (since there are 1000 mL in 1 L)
To convert mL to L, we divide by 1000:
Volume of solution = 0.075 L
The molar mass of magnesium chloride (MgCl2) can be calculated using the atomic masses:
Molar mass = (mass of Mg) + 2 x (mass of Cl)
Mass of Mg = 24.31 g/mol (from periodic table)
Mass of Cl = 35.45 g/mol (from periodic table)
Molar mass of MgCl2 = 24.31 + 2 x 35.45 = 95.21 g/mol
Now we can substitute the given values into the equation:
Grams of solute = (200 M) x (0.075 L) x (95.21 g/mol)
By multiplying the values, we get:
Grams of solute = 1425.75 g
Therefore, there are 1425.75 grams of magnesium chloride in 75.0 mL of a 200 M solution.
How many grams of magnesium chloride are in 75.0 mL of a 200 M solution of magnesium chloride in water? porbvide working out
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