how many grams of magnesium carbonate are in a sample that has 1.58 x 10^24 oxygen atoms?

Answer 1

how many sulfur atoms are in 2.57 g of iron (III) sulfate?

Answer 2

MgCO3.
mols O atoms = 1.58E24/6.02E23 = ?
mols MgCO3 = 1/3 of that.
g MgCO3 = mols MgCO3 x molar mass MgCO3.

Answer 3

mols Fe2(SO4)3 = grams/molar mass = ?
mols S atoms is 3x that.
1 mol S atoms will contain 6.02E23 atoms; therefore, 3 mols will be >>>>>>.

Answer 4

73.7g

Answer 5

1.16 x 10^22 sulfur atoms