How many grams of lithium hydroxide are needed to remove 920 g of carbon dioxide in the air

Answer 1

first you need to write out the balanced reaction equation of LiOH reacting with CO2.
So...

2LiOH + CO2--->Li2CO3 + H2O

You start with 920 g CO2 and use this equation to convert to moles CO2 and then to moles LiOH. There are 2 moles LiOH for every 1 mole of CO2. And finally convert to grams of LiOH.

Answer 2

Paul gave it to you straight.