How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution reacts with excess aluminum metal? Show all of the work needed to solve this problem.

Question

2 Al (s) + 3 Fe(NO3)2 (aq) yields 3 Fe (s) + 2 Al(NO3)3 (aq)

DrBob222 · Answer

See your problem above with Mg and HCl. This is the same type of problem. The 80.5% is handled this way. 285g impure iron(II) nitrate x 0.805 = ? g pure iron(II) nitrate

Anonymous · Answer

245 x 0.8= 196/242=0.81