How many grams of ice at 0°C and 101.3 kPa (standard pressure) could be melted by the addition of 0.80 kJ of heat?

Answer 1

Note that the process involved here is the phase change of ice, from solid (ice) to liquid (water). Thus, the heat involved is latent heat, not sensible heat.
The latent heat of fusion of ice is approximately 334 J/g. You can look for this value in textbooks or google.
Then we use the formula,
Q = m*Lf
where
m = mass (g)
Lf = latent heat of fusion

Substituting (note that 1 kJ = 1000 J),
0.80 kJ * (1000 J / 1 kJ) = m * 334 J/g
m = 800 / 334
m = 2.40 g

hope this helps~ `u`