I2 + 2S2O3^2- ==> 2I^- + S4O6^2-
mols S2O3^2- = M x L = ?
1 mol I2 = 2 mol S2O3^2-; therefore, mols S2O3^2- = 2*mols I2.
Then M S2O3^2- = mols S2O3^2-/L S2O3^2-
How many grams of I2 are present in a solution if 33.75mL of 0.140M Na2S2O3 solution is needed to titrate the I2solution?
1 answer