Dear Sally,
Here is the balanced equation
HCL(aq) + NAOH(aq)---- NACL(s)+ H20(l)
Number of moles in the NAOH(aq)=
40/(23+16+1)
=1
as 1 mole of HCL will react with 1 mole of the Naoh solution
number of mole of HCL required= 1
Still remember that there is a equation
mol= g/molar mass
Let the number of grams of HCL needed be g grams
the number of grams of HCL required=
1= g/(1+35.5)
g=36.5
Therefore, 36.5 grams of HCL is required
Hope it helps!!
How many grams of hydrochloric acid should we use so we have exactly enough to react with 40g of sodium hydroxide? You'll need to write a chemical reaction, balance it, and then perform your calculation.
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