How many grams of H2O (Mm = 18.0 g/mol) are produced in the combustion of 70.0 g of C4H10 (Mm = 58.1 g/mol)?

Question

How many grams of H2O (Mm = 18.0 g/mol) are produced in the combustion of 70.0 g of C4H10 (Mm = 58.1 g/mol)?
2C4H10 + 13O2  8CO2 + 10H2O

DrBob222 · Answer

mols C4H10 = grams/molar mass Using the coefficients in the balanced equation, convert mols C4H10 to mols H2O. Now convert mols H2O to grams. g = mols H2O x molar mass H2O.