heat lost by Cu + heat gained by Fe = 0
[mass Cu x specific heat Cu x (Tf-Ti)] + [mass Fe x specific heat Fe x (Tf-Ti) = 0
Substitute and solve for mass Fe
Post your work if you get stuck.
How many grams of Fe can be heated from 40.0oC to 60.0oC when 20.0 g of Cu cools from 100.0oC to 25.0oC?
Specific heat of Fe = 0.444 J/(g oC); specific heat of Cu = 0.382 J/(g oC)
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