How many grams of dichloromethane are formed from 1500.0 grams of methane, it the percent yield for the reaction is 82.5%?

Answer 1

You don't have an equation to use; is this it?
CH4 + 2Cl2 ==> CH2Cl2 + 2HCl

mols CH4 = grams/molar mass = 1500/16 = approx 100 but you need to do it more accurately.
Using the coefficients in the balanced equation, convert mols CH4 to mols of Ch2Cl2. That will be approx 100 x (1 mol CH2Cl2/1 mol CH4) = approx 100 mols CH2Cl2.
Grams CH2Cl2 = approx 100 mols x molar mass = 100 x approx 81 = approx 8100 grams if the reaction were 100%. This is the theoretical yield (TY). You want to find the actualyield (AY)
%yield = [AY/TY]*100
You know the %yield and the TY, solve for (AY).