How many grams of copper are deposited on the cathode of an electrolytic cell if an electric current of 2.00 A is passed through a solution of CuSO4 for a period of 19.0 min?

3 answers

coulombs - A x seconds = ?
096,485 coulombs will deposit 63.55/2 g Cu = approx 32 but you need a better number than that.
Then 32? x coulombs/96,485 = g Cu deposited.
what are the coulombs? how do I find them?

and also where can I find that equation?
See my first line. Not only did I tell you that you needed coulombs but I told you how to calculate it.
coulombs = A x seconds.
amperes in the problem = 2.00 A.
time in the problem = 19.0 min or 19.0 x (60 seconds/min) = ? seconds so
coulombs = 2.00 x 19.0 x 60 = >