2C4H10 + 13O2 ==> 8CO2 + 10H2O
mols O2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols O2 to mols CO2.
Now convert mols CO2 to grams. g = mols x molar mass
how many grams of CO2 are produced when 88 grams of O2 are reacted with an excess of butane?
1 answer