How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7gFe? Fe2O3(s) + 3CO(g) => 3CO2(g) + 2Fe(s)

Answer 1

Convert 209.7 g Fe to mols. molsl = grams/molar mass
Using the coefficients in the balanced equation, convert mols Fe to mols CO.
Now convert mols CO to grams. g = mols x molar mass.

Answer 2

Moles Fe = 209.7 g / 55.847 = 3.75
the ratio between CO and Fe is 3 : 2
Moles CO needed = 3.75 x 3 / 2 = 5.63
Mass CO = 5.63 mol x 28.01 g/mol =157.7 g

Answer 3

is this right?

Answer 4

I'm not an expert on this subject, but I think that I understand it. The numbers that seem to come out of nowhere are the atomic masses of the various elements and compounds, and the calculations for those are all correct.