To calculate the number of grams of CO2 gas occupying 59.9 L at STP, we first need to find the number of moles of CO2 present.
At STP (Standard Temperature and Pressure), the conditions are 0°C (273.15 K) and 1 atm pressure. The molar volume of gas at STP is 22.4 L/mol.
Given that the volume is 59.9 L, we can calculate the number of moles of CO2 present:
moles = volume / molar volume
moles = 59.9 L / 22.4 L/mol
moles ≈ 2.6786 mol
Now, we can use the molar mass of CO2 to find the mass of CO2 in grams:
molar mass of CO2 = 12.01 g/mol (C) + 2(16.00 g/mol) (O)
molar mass of CO2 = 44.01 g/mol
mass = moles * molar mass
mass = 2.6786 mol * 44.01 g/mol
mass ≈ 118.0 g
Therefore, approximately 118.0 grams of CO2 gas occupy 59.9 L at STP.
How many grams of CO_2 gas occupy 59.9 L at STP? Round your answer to 3 significant figures.
Note: Reference the Fundamental Constants table for additional information.
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