How many grams of bromine gas will be produced when 25.54 grams of silver bromide solid decomposes fully? Must show the correct stoichiometric set up for calculation. 2-5 sentences

Answer 1

To calculate the amount of bromine gas produced when 25.54 grams of silver bromide decomposes fully, we first need to determine the molar mass of silver bromide. The molar mass of AgBr is 187.772 g/mol. From the chemical equation for the decomposition of silver bromide (2AgBr -> 2Ag + Br2), we know that 1 mole of silver bromide produces 1 mole of bromine gas. Therefore, 25.54 grams of AgBr is equal to 0.136 moles of AgBr. Using the stoichiometry of the reaction, we can determine that 0.136 moles of AgBr will produce 0.136 moles of bromine gas. Finally, multiplying the moles of bromine gas by the molar mass of bromine (79.904 g/mol) we find that 25.54 grams of AgBr will produce 10.88 grams of bromine gas.