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How many grams of ammonium nitrate nedd to be added to 500g of water so that the freezing point becomes -8.3 °C?

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-8.3=-.52*molesammonuimNO3/.5

gramsNH4NO3=molmass*8.3/.52*.5
look up the formula mass of ammonium nitrate, and solve.

Can you please give me the formula

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