Initial mass of H2SO4 = final mass of H2SO4 in solution
Initial mass is (87.0%) of target solution (X).
Final mass is (35.5%) of the initial solution (200g).
X = 200g * 35.5/87.0
How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 percent by mass solution? Show all of the work needed to solve this problem.
2 answers
chemistry is the most boring subject in the universe. :(